A right angle ABC with sides 3cm,4cm,5cm is revolved about the fixed side of 4cm. find the total surface area and curved surface area of solid generated

The volume is 37.7142 cm^337.7142cm

3

and total surface area is 75.428 cm^275.428cm

2

We are given that A right angle triangle ABC with sides 3 cm, 4 cm, 5 cm is revolved about the fixed side of 4 cm

So, height of the cone so formed is 4 cm

Radius of the cone = 3 cm

Slant height = 5 cm

Volume of cone = \frac{1}{3} \pi r^2 h

3

1

πr

2

h

= \frac{1}{3} \times \frac{22}{7} \times 3^2 \times 4

3

1

×

7

22

×3

2

×4

= 37.7142 cm^337.7142cm

3

Total surface area of cone = \pi rl +\pi r^2πrl+πr

2

= \frac{22}{7} \times 3 \times 5 + \frac{22}{7} \times 3^2

7

22

×3×5+

7

22

×3

2

= 75.428 cm^275.428cm

2

Hence the volume is 37.7142 cm^337.7142cm

3

and total surface area is 75.428 cm^275.428cm

2