Fausta
Jan 18, 2021

answers: 1

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Answer:

The volume is 37.7142 cm^337.7142cm

3

and total surface area is 75.428 cm^275.428cm

2

We are given that A right angle triangle ABC with sides 3 cm, 4 cm, 5 cm is revolved about the fixed side of 4 cm

So, height of the cone so formed is 4 cm

Radius of the cone = 3 cm

Slant height = 5 cm

Volume of cone = \frac{1}{3} \pi r^2 h

3

1

πr

2

h

= \frac{1}{3} \times \frac{22}{7} \times 3^2 \times 4

3

1

×

7

22

×3

2

×4

= 37.7142 cm^337.7142cm

3

Total surface area of cone = \pi rl +\pi r^2πrl+πr

2

= \frac{22}{7} \times 3 \times 5 + \frac{22}{7} \times 3^2

7

22

×3×5+

7

22

×3

2

= 75.428 cm^275.428cm

2

Hence the volume is 37.7142 cm^337.7142cm

3

and total surface area is 75.428 cm^275.428cm

2

494

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Jan 18, 2021

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