The side of a square exceeds the side ofanother square by 5 cm. The difference oftheir areas is 325 sq. cm. Find the sides ofeach square.​

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A side of square exceeds the side of another square by 4 cm and the sum of area of two squares is 400 cm sq. How to find the dimensions of the squares?

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Ruhaizat Ooi

Answered September 24, 2018

Let the sides of Square A be “x” cm,

and the sides of Square B be “x + 4” cm.

Hence, sum of area of two squares A abd B are :

x^2 + (x +4)^2 = 400

x^2 + (x^2 + 8x + 16) = 400

2x^2 + 8x + 16 = 400

x^2 + 4x + 8 = 200

x^2 + 4x - 192 = 0

(x - 12)(x + 16) = 0

therefore, x = 12, or -16.

Substitute x = 12 into first equation, we have

144 + (16)^2 = 400

144 + 256 = 400 QED.

dimension of Square A is 12cm

dimension of Square B is 16cm