Given : R=2Ω l=1 m d=0.4 mm =0.0004 m
Cross section area of wire A=
4
πd
2
=
π×(0.0004)
=1.256×10
−7
m
Resistivity of the material ρ=
l
RA
∴ ρ=
1
2×1.256×10
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