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Take a 1 m long thread of negligible mass. Consider three spherical/ cuboidal bobs of

same sizes but different masses. Form simple pendulum using thread and bob, and estimate

the time period of each of the pendulum by recording time for 20 oscillation three times

for each pendulum formed. Tabulate the observations taken. Interpret your results and

justify. List your 2 main conclusions derived from the above project.

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answers: 1
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My two main conclusions derived from the given project are-

The time period of all the bobs would be the same.

Time period will not depend on the mass of bobs as they are suspended from the thread of the same length.

A hefty point mass (referred to as the "bob") is linked to one end of a string that is perfectly extendable, flexible, and weightless to create the perfect basic pendulum. It hangs from a solid or rigid support.

A simple pendulum's time period, designated by the letter "T," is the amount of time it takes to complete one complete oscillation.

The time period for any simple pendulum can be written as,

T = 2π/ω = 2π × √(L/g)

Here, T is the time period, g is the gravitational force, and L is the length of the pendulum.

As we can see from this equation, the time period does not depend on the mass of the bob.

Hence, in the given project all the three spherical/cuboidal bobs of different masses but same sizes will have the same time period.

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