It is given that f(0)=1 and f(1)=4 for the polynomial f(x)=4x
3
−3x
2
+2x+k, therefore, we substitute the values and find the value of k as shown below:
Whenf(0)=1
f(0)=4(0)
3
−3(0)
2
+2(0)+k
⇒1=k
Whenf(1)=4
f(1)=4(1)
3
−3(1)
2
+2(1)+k
⇒4=4−3+2+k
⇒4=3+k
⇒k=4−3
⇒k=1
We conclude that, in both the cases k=1, thus, we substitute k=1 in f(x):
f(x)=4x
3
−3x
2
+2x+1
Hence, f(x)=4x
3
−3x
2
+2x+1.